Question

Prove that (sinA*tanA)+cosA=secA

Answer 1

Step-by-step explanation:

Hello mate here is your answer

(SinA×TanA)+CosA

(sinA×sinA/cosA)+ cos A

sin^2A/CosA+CosA

(sin^2+ cos^2)/CosA.

$\sin( {a}^{2} ) + \cos( {a}^{2} ) = 1$

1/cosA

so secA