Question

prove that sinAcosA(tanA + cosA) = 1

Answer 1

Hello Friend,

Here, there needs a correction in your question. LHS should be
sin A cos A (tan A + cot A)

LHS
= sin A cos A (tan A + cot A)
= sin A cos A ((sin A/cos A) + (cos A/sin A))
= sin A cos A [ (sin² A + cos²A) / (sin A cos A) ]

[Now, sin²A + cos²A = 1]

= sin A cos A (1) ÷ (sin A cos A)
= 1
= RHS

Hence proved.


Hope it helps.

Purva
@Purvaparmar1405
Brainly.in

Answer 2

Hey there !!!!

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=sinAcosA(tanA+cotA)

tanA= sinA/cosA   cotA=cosA/sinA

=sinAcosA(sinA/cosA+cosA/sinA)

=sinAcosA(sinA*sinA+cosA*cosA)/sinAcosA

=sin²A+cos²A

=1

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Hope this helped you...........