Math, asked by yogesh46, 1 year ago

prove that sinAcosA(tanA+cotA)=1

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Answered by shritisinha563

2

sinAcosA(tanA+cotA)=
sinAcosA{(sinA/cosA)+(cosA/sinA)}=
sinAcosA((sin^2A+cos^2A)/(sinAcosA))=1
(proved)

yogesh46: thank you so much

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