Question

prove that (sinb+Sina)/(cosb-cosa)=(cosa+cosb)/(sina-sinb)

Answer 1

Hi Friend !!!

Here is ur answer !!!

$\frac{sin \: b \: + sin \: a}{cos \: b - cos \: a} = \frac{cosa + cosb}{sina - sinb} \\ \\ (sina + sinb)(sina - sinb) = (cosa + cosb)(cosb - cosa) \\ \\ {sina}^{2} - {sinb}^{2} = {cosb}^{2} - {cosa}^{2} \\ \\ sin(a - b)sin(a + b) = sin(a - b)sin(a + b) \\ \\ hence \: proved \:$

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