Prove that sine square (π/8+A/2) -sun square (π/8-A/2)=1/√2 sinA answer
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Answer:
Using
sin
2
A−sin
2
B=sin(A+B)sin(A−B)
we get
LHS =sin(π/8+A/2+π/8−A/2)sin(π/8+A/2−π/8−A/2)=sin(π/4)sinA=(1/
2
)sinA= RHS
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