Question

Prove that sinº A+ cos4 A +2sin? A.cos? A =1.
​

Answer 1

Step-by-step explanation:

I think the question should be

sin⁴A + cos⁴A + 2sin²A.cos²A = 1

Since we can write it :

L.H.S. = (sin²A)² + (cos²A)² + 2sin²A.cos²A

Now it is in the form of a² + b² + 2ab => (a + b)²

So, (sin²A)² + (cos²A)² + 2sin²A.cos²A => (sin²A + cos²A)²

We know that sin²A + cos²A = 1.

Therefore, (1)² = 1

L.H.S = R.H.S.

Hence Proved.

Hope you got your answer

Have a great day ahead

Take care

Answer 2

Answer:

___YOUR CORRECT ANSWER___

Step-by-step explanation:

Answer

We, have

LHS = sin

4 A + cos 4A

⇒ LHS = (sin 2

A) 2 +(cos 2

A) 2 +2sin

2 Acos 2 A−2sin 2Acos 2

A [Adding and subtracting 2 sin 2 A cos 2 A ]

⇒ LHS = (sin 2 A+cos 2 A) 2 −2sin 2 Acos A=1−2sin 2 Acos 2 A=RHS..

✌❣✨ KEEP SMILING ✨❣✌