Question

prove that ( sintheta + cosec ² theta. ) ² + ( cos theta + sec² theta) ²​

Answer 1

Answer:

L.H.S. =(sinθ+cosecθ)

2

+(cosθ+secθ)

2

=sin

2

θ+cosec

2

θ+2sinθ.cosecθ+cos

2

θ+sec

2

θ+2cosθ.secθ

=(sin

2

θ+cos

2

θ)+1+cot

2

θ+2+1+tan

2

θ+2

=1+6+tan

2

θ+cot

2

θ

=7+tan

2

θ+cot

2

θ

= R.H.S.

Explanation: