Prove that (sintheta+cosectheta)^2 + (costheta+sectheta)^2 = 7+tan^2+cot^2
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Answer:
Step-by-step explanation:
(sinA+cosecA)^2+(cosA+secA)^2=7+tan^2A+cotA^2
sin^2A+cosec^2A+2cosecAsinA+cos^2A+seC^2A+2cosAsecA
(sin^2A+cos^2A=1)
1+1+cot^2A+1+tna^2A+2*sinA(1/sinA)+2*cosA(1/cosA)
1+1+cot^2A+1+tan^2A+4
7+tan^A+cot^2A
HOPE U ENJOY!!!!
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