Math, asked by starboyk8029, 1 year ago

Prove that (sintheta+cosectheta)^2 + (costheta+sectheta)^2 = 7+tan^2+cot^2

Answers

Answered by vasanmass61
1

Answer:


Step-by-step explanation:

(sinA+cosecA)^2+(cosA+secA)^2=7+tan^2A+cotA^2

sin^2A+cosec^2A+2cosecAsinA+cos^2A+seC^2A+2cosAsecA

(sin^2A+cos^2A=1)

1+1+cot^2A+1+tna^2A+2*sinA(1/sinA)+2*cosA(1/cosA)

1+1+cot^2A+1+tan^2A+4

7+tan^A+cot^2A

HOPE U ENJOY!!!!

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