Question

prove that (sinx+cosx)/(sinx-cosx) + (sinx-cosx)/(sinx+cosx)=2/(sin2x-cos2x)​

Answer 1

Answer:

"consider the left side"

sin^2x-cos^2x" is a "color(blue)"difference of squares"

"which factorises, in general"

•color(white)(x)a^2-b^2=(a-b)(a+b)

rArr(sin^2x-cos^2x)/(sinx+cosx)

=((sinx-cosx)cancel((sinx+cosx)))/cancel((sinx+cosx))

Answer 2

Answer:

Refer to attachment...