Prove that sn,s2n-sn,s3n-s2n,s4n-s3n are in AP. find out the common difference
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we know that common difference is same in AP
so,term2 -term1=term3-term2
(s2n-sn)-sn=(s3n-s2n)-(s2n-sn)
s2n-sn-sn=s3n-s2n-s2n+sn
s2n-s2n=s4n-s4n
0=0
therefore sn,s2n-sn,s3n-s2n,s4n-s3n are in AP
so,term2 -term1=term3-term2
(s2n-sn)-sn=(s3n-s2n)-(s2n-sn)
s2n-sn-sn=s3n-s2n-s2n+sn
s2n-s2n=s4n-s4n
0=0
therefore sn,s2n-sn,s3n-s2n,s4n-s3n are in AP
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