Prove that square of an positive integer os of the form 4n or 4n+1 for some integer n
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Let a be any positive integer.
a=bn+r
a=4n+r
0≤r<4
The possible values of r are 0,1,2 and 3.
a={1,2,3,4.......}
Square of any positive integer:-
1²=1=4(0)+1 (r=1)
2²=4=4(1)+0 (r=0)
3²=9=4(2)+1 (r=1)
4²=16=4(4)+0 (r=0)
Therefore,the square of any positive integer is of the form 4n or 4n+1 for any integer n.
Hence proved
a=bn+r
a=4n+r
0≤r<4
The possible values of r are 0,1,2 and 3.
a={1,2,3,4.......}
Square of any positive integer:-
1²=1=4(0)+1 (r=1)
2²=4=4(1)+0 (r=0)
3²=9=4(2)+1 (r=1)
4²=16=4(4)+0 (r=0)
Therefore,the square of any positive integer is of the form 4n or 4n+1 for any integer n.
Hence proved
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