Prove that square of any positive even integer is always even.
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HEY MATE HERE IS YOUR ANSWER:
Suppose n=2mn=2m is an even integer. Since n=2mn=2m , then n2=(2m)2n2=(2m)2
n2n2 = (2m)2(2m)2 = 4m24m2
=2(2m2)2(2m2)
Since (2m2)(2m2) is an integer and 2(2m2)2(2m2) is in the form 2m2m , we have proven that the square of an even integer is even.
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Suppose n=2mn=2m is an even integer. Since n=2mn=2m , then n2=(2m)2n2=(2m)2
n2n2 = (2m)2(2m)2 = 4m24m2
=2(2m2)2(2m2)
Since (2m2)(2m2) is an integer and 2(2m2)2(2m2) is in the form 2m2m , we have proven that the square of an even integer is even.
HOPE THIS HELPS YOU....
PLEASE MARK IT AS BRAINLIEST...
Answered by
1
Answer:
Qed
Step-by-step explanation:
We can represent eve n number by 2n
So square wouldbe 4n^2
= 2×(2n^2) = even
Qed
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