prove that square root of 2 + square root of 3 are irrational
Answers
Answered by
2
Hi Renuka,
Lets think root of 2 + root of 3 = x
Then, 2 + 2 root 6 + 3 = x square
Root 6 = x square - 5
As the set of rational numbers is closed under multiplication and addition x square - 5 is irrational and we even know that root 6 is irrational.
So root 2 + root 3 is irrational
Lets think root of 2 + root of 3 = x
Then, 2 + 2 root 6 + 3 = x square
Root 6 = x square - 5
As the set of rational numbers is closed under multiplication and addition x square - 5 is irrational and we even know that root 6 is irrational.
So root 2 + root 3 is irrational
Answered by
0
Answer:
Explanation:Let √3 be a rational number
i.e. √3 = a/b where a,b ∈ integers having no common factor other then 1 and b≠0
= √3 = a/b
square both the sides
= 3= a²/b2
= a² = 3b²
= b² = a²/3
= 3 divides a²
= 3 divides a²
let a²= 3c
= b²=9c²/3
= b²= 3c²
= c²= b²/3
= 3 divides b²
= 3 divides b
thus 3 is a common factor of a and b
this contradicts the fact that a and b are coprime numbers i.e. having no common factor other then 1.
therefore √3 is not a rational number
hence it is irrational
hope it helps u.please mark it as the best.
Similar questions
Computer Science,
8 months ago
Chemistry,
8 months ago
English,
1 year ago
Geography,
1 year ago
English,
1 year ago