prove that square root of 3 is a irrational number
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Step-by-step explanation:
root 3= p/q
sharing on both sides
3=p square/ q square
3q square = p square .... equ1
root 3 divides p
p = 3m
p square = 6 m square ... equ2
2 -1
p square = 3 q square
6 m square = 3 q square
q square = 3 m square
3 divides q
which is a contradiction so root 3 is an irrational number
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