Question

Prove that sum of any two sides of a triangle is greater than the third side.
URGENT​

Answer 1

Answer:

AD^2=BC^2+AB^2

Step-by-step explanation:

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Answer 2

Answer:

let triangle be and

let angle a be 3x

let angle b be 2x

let angle c be x

3x+2x+x=180

6x=180

x=180/6

x=30

angle a =3x=3×30=90

angle b=2x=2×30=60

angle c=x=1×30=30