prove that sum of exterior angle of quadrilateral is 360
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Let sum of all exterior angles be 'E', and sum of all interior angles be 'I'. E = n × 180° - (n -2) × 180°. Hence, The sum of all the exterior angles of a polygon is 360° .
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the sum of angles of triangle《A+《B+《C=180degree
so according to triangle there ate 3 sides in triangle =180
now quadrilateral it has 4 angles
=《A+《B +《C+《D
=360degrees
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