Question

Prove that sum of interior angles in a square is 360°

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Answer 1

Answer:

Let us use the formula:-

• (N - 2) × 180

• Where N is number of sides

Let us solve:-

$\sf(4 - 2) \times 180$

$\sf \to(4 - 2) \times 180$

$\sf \to2 \times 180$

$\sf \to360 \degree$

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• The number of sides in a square is 4

• All the angles are 90°

Answer 2

Draw one of it's diagonals.

Now the quadrilateral is divided into 2 triangles.

Now in triangle ABD

1 + 2 + 3 = 180°

In triangle BCD

4 + 5 + 6 = 180°

So 1+2+3+4+5+6 = 360°

= A + B + C + D = 360°

Hence proved