Question

Prove that sum of interior angles in a square is 360°

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Answer 1

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Let us use the formula:-

• (N - 2) × 180

• Where N is number of sides

Let us solve:-

$\sf(4 - 2) \times 180$

$\sf \to(4 - 2) \times 180$

$\sf \to2 \times 180$

$\sf \to360 \degree$

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• The number of sides in a square is 4

• All the angles are 90°

Answer 2

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⇒ ∠A + ∠B + ∠C + ∠D = 360° [using (i) and (ii)]. Hence, the sum of all the four angles of a quadrilateral is 360°.