Question

Prove that sum of interior angles in a triangle is 180°


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Answer 1

Answer:

Let us use the formula:-

• (N - 2) × 180

• Where N is number of sides

Let us solve:-

$\sf(3 - 2) \times 180$

$\sf \to(3 - 2) \times 180$

$\sf \to1 \times 180$

$\sf \to180 \degree$

Answer 2

Answer:

Let us use the formula:-

(N - 2) × 180

Where N is number of sides

Let us solve:-

$\sf(3 - 2) \times 180$

$\sf \to(3 - 2) \times 180$

$\sf \to1\times 180$

$\sf \to180 \degree$

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