Question

Prove that sum of interior angles in a triangle is 180°

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Answer 1

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$\huge{ \sf{{ \underline{formula \: used : }}}}$

$\bf \blue\bigstar{(n - 2)} \times 180 \degree$

$\blue \bigstar \bf{(n) \: be \: the \: number \: of \: sides}$

$\huge{ \sf{{ \underline{\: solution : }}}}$

$\bf(3 - 2) \times 180 \degree$

$\to\bf(3 - 2) \times 180 \degree$

$\to\bf(1) \times 180 \degree$

$\bf \to180 \degree$

Answer 2

Answer:

$\huge \green{\fbox { \fbox{{\: answer : }}}}$

$\huge{ \sf{{ \underline{formula \: used : }}}}$

$\bf \blue\bigstar{(n - 2)} \times 180 \degree$

$\blue \bigstar \bf{(n) \: be \: the \: number \: of \: sides}$

$\huge{ \sf{{ \underline{\: solution : }}}}$

$\bf(3 - 2) \times 180 \degree$

$\to\bf(3 - 2) \times 180 \degree$

$\to\bf(1) \times 180 \degree$

$\bf \to180 \degree$