Prove that sum of interior angles of a triangle is 180°.
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GIVEN : A triangle ABC
TO PROVE: <A + <B + <C +<D =180°
CONSTRUCTION: Draw a line l parallel to BC.
PROOF: since l parallel to BC
Therefore,
<2=<4 [ alternate interior angles]
<3=<5 [ alternate interior angles]
Now,
<2+<3=<4+<5
Adding <1 on both sides
=><1+<2<3=<1+<4+<5
sum of angles at point on line is 180°
=> <1+<2+<3=180°
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:- it's pagal
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