Prove That sum of measure of all angles in triangles is 180°
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Answer:
Step-by-step explanation:
Given : ABC is a triangle
RTP : ∠ABC + ∠CAB + ∠ACB = 180°
Construction ; draw EF ║ BC through A
Proof :
∠ABC = ∠ EAB (ALTERNATE ANGLES)
∠BCA = ∠FAC (ALTERNATE ANGLES)
∠EAB + ∠BAC + ∠FAC = 180° (SUM OF ALL LINEAR ANGLES AT A )
SUBSTITUTE : ∠EAB = ∠ABC AND ∠FAC = ∠BCA
SO ,
∠ABC + ∠CAB + ∠ACB = 180°
HENCE , PROVED
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• Sum of measures of all angles of a triangle is 180°.
More To Know :-
• A triangle is a polygon with three edges and three vertices.
• A triangle with vertices A, B and C is denoted as ∆ABC.
• Sum of all angles of a triangle is always 180°.
• The measure of an exterior angle is sum of it's two interior angles that are not adjacent to it.
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