Question

prove that sum of nth term of an AP is n/2{2a+(n-1) d}
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Answer 1

Answer:

Here, a = 67 and d= -13

Sn = n/2[2a+(n-1)d]

S20 =20/2[2×67+(20-1)(-13)]

S20= 10[134 – 247]

S20 = -1130

So, the sum of the first 20 terms is -1130.

Step-by-step explanation:

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Answer 2

Answer:

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