Prove that sum of the angle of triangle is 180 degree.
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Given: In ∆PQR, ∠1, ∠2 and ∠3 are the angles of ∆PQR. To prove: ∠1 + ∠2 + ∠3 = 180° Construction: We draw a line XPY parallel to QR through the opposite vertex P. Proof: Line XPY || QR and XPY is a line Therefore ∠4 + ∠1 + ∠5 = 180° …(1) But XPY || QR and PQ, PR are transversal. So ∠4 = ∠2 and ∠5 = ∠3 (Pairs of alternate angles) Putting values of ∠4 and ∠5 in Eqn. (1) ∠2 + ∠1 + ∠3 = 180° => ∠1 + ∠2 + ∠3 = 180°Read more on Sarthaks.com - https://www.sarthaks.com/857565/prove-that-the-sum-of-angles-of-a-triangle-is-180
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the sum of angle of triangle is 180 degree because the all sides of triangles have measure 60 degree that's that's called the sum of triangle is 180 degree
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