Question

Prove that sum of the angles of a triangle is 180°.if in ∆ABC,∆A+angles B =120 and angle B+angle C=100, then find angle B

Answer 1

angle A + angle B + angle C = 180°

120°+ angle C = 180°

angle C = 180°-120°

angle C = 60°

Angle A + 100°= 180°

Angle A = 180°-100°

Angle A = 80°

Angle A + Angle B + Angle C = 180°

80° + Angle B + 60° = 180°

Angle B = 180°-140°

Angle B = 40°

Answer 2

Answer:

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Step-by-step explanation:

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