Question

Prove that sum of the square of the sides of parallelogram is equals to sum of the square of its diagonals ​

Answer 1

Answer:

i.e. O is the mid point of AC and BD. In ∆ABD, point O is the midpoint of side BD. In ∆CBD, point O is the midpoint of side BD. Hence, the sum of the squares of the diagonals of a parallelogram is equal to the sum of the squares of its sides.