Question

Prove that sum of the squares of the diagonals of a parallelogram is
equal to the sum of the squares of its sides.​

Answer 1

Answer:

O is the mid point of AC and BD. In ∆ABD, point O is the midpoint of side BD. In ∆CBD, point O is the midpoint of side BD. Hence, the sum of the squares of the diagonals of a parallelogram is equal to the sum of the squares of its sides.

Answer 2

Answer:

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