Question

Prove that sum of three consecutive integers is 6

Answer 1

let the number = x

second number = x+1

third number = x+2

$x + x + 1 + x + 2 = 6 \\ 3 + 3 = 6 \\ 3x = 6 - 3 \\ 3x = 3 \\ x = \frac{3}{3} = 1 \\ x = 1$

1st no.=1
2nd no.=1+1=2
3rd no.=1+2=3

consecutive no. 1+2+3=6

Answer 2

given x+x+1+x+2=6
3x+3=6
3x=6-3=3
x=3/3=1
x+x+1+x+2=1+2+3=6