prove that sum of two sides is always greater than the third side
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As we all know, In a Triangle, sum of three sides are 180°.
Therefore, <A + <B + <C = 180°
so, (<A + <B) » <C
So, the side opposite to <C is smaller than the sum of the opposite sides of <A and <B.
Therefore, <A + <B + <C = 180°
so, (<A + <B) » <C
So, the side opposite to <C is smaller than the sum of the opposite sides of <A and <B.
Sparsh11:
No it is not the right answer
Yes
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