prove that sum of x+y and x-y is twice of xth term?
tanishq972003:
it is a arithmetic progression question this is not that simple please answer
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Answered by
0
a1= x+y
a2=x-y
d= a1-a2
=x-y-x-y
=-2y
n=2
s=(n/2)[2a +(n-1)d]
=(2/2)[2(x+y) + (2-1)*(-2y)]
=1*[ 2x+2y+ 1*(-2y)]
=[2x+2y-2y]
=2x
a2=x-y
d= a1-a2
=x-y-x-y
=-2y
n=2
s=(n/2)[2a +(n-1)d]
=(2/2)[2(x+y) + (2-1)*(-2y)]
=1*[ 2x+2y+ 1*(-2y)]
=[2x+2y-2y]
=2x
sorry but it is ap question so you have a wrong answer
OK please tell right answer
Answered by
0
x + y + x - y
here the y term gets cancelled and become 0 as one is positive and another is negative with same magnitude
= x + x
= 2x
here the y term gets cancelled and become 0 as one is positive and another is negative with same magnitude
= x + x
= 2x
hey mate this is a ap question so you don't wrong answer
please tell right answer
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