Question

prove that summision 3^r.nCr = 4^n​

Answer 1

Answer:

doesn't seemed to be solvable with the knowledge of class 12.

recheck the qus please and let me know if i can help.

Step-by-step explanation:

Please follow and support!

Answer 2

L.H.S = 30C(n,0) + 31 C(n,1) + 32 C(n,2) + --- 3r(n, r) + --- +3n C(n, n)  

       = C(n,0) + C(n,1) 31 + C(n,2) 32 + C(n,3) 33 + --- +C(n,n)3n

This is in the form of (1+3)n  

       = (1+3)n = 4n = R.H.S