Question

Prove that (tan 0+2) (2tan 0+1)=5tan 0+sec square 0

Answer 1

Answer:

ANSWER

5tan2θ−5sec2θ=5(tan2θ−sec2θ) 

We know that

tan2θ+1=sec2θ⇒tan2θ−sec2θ=−1∴5(−1)=−5