Question

prove that tan /1-cot+cot/1-tan = 1+sec *cos

Answer 1

Step-by-step explanation:

tan/1-cot + cot/1-tan

=(sin/cos)/(sin-cos/sin)+(cos/sin)/(cos-sin/sin)

=sin²/cos(sin-cos)-cos²/sin(sin-cos)

=sin³-cos³/sincis(sin-cos)

=(sin-cos)(1+sincos)/sincos(sin-co

=1+sincos/sincos

=1+sec cosec

Answer 2

Step-by-step explanation:

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