Question

Prove That:
tanθ/1-cotθ + cotθ/1-tanθ = 1/secθ-tanθ

Answer 1

Answer:

the answer will be

Step-by-step explanation:

$\tan( \alpha ) (1 - \tan( \alpha ) ) + \cot( \alpha )(1 + \cot( \alpha )$

tan-tan²+cot-cot²/1(1-tan) -cot(1-tan)

tan+cot-(tan²+cot²)/1-tan-cot+cottan

tan+cot-1/1-tan-cottan just solve this u get urs answer perfectly