Question

prove that tanθ + 1/tanθ = secθ cosecθ

Please answer fast

Answer 1

Step-by-step explanation:

tan@+(1/tan@)

=(tan^2@+1)/tan@

=sec^2@/tan@

=sec^2@*(cos@/sin@)

=(1/cos^2@)*(cos@/sin@)

=(1/cos@)*(1/sin@)

tan@+(1/tan@)=sec@*cosec@

Answer 2

Step-by-step explanation:

we know sec^2 θ - tan^2 θ=1

so

tanθ + 1/tanθ = secθ cosecθ

• tan^2 θ+1/tan θ
• sec^2 θ/tan θ
• sec θ×secθ/tan θ
• sec θ×1/cosθ/sinθ/cosθ
• secθ.cosecθ