prove that tan-1 ( x+rootx/ 1- x3/2 ) =Tan-1x
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We know that tan(x+y)=[tan x + tan y]/[1-tan x*tan y]
Let tan x =a and tan y=b
Thus
x=tan-1 a
y=tan-1 b
Thus…tan-1 a+tan-1 b=tan-1[(a+b)/1-ab)]…eqn(1)
As [√x]^3=x√x
Thus…in the question…
a=x
b=√x
Plug in these two values in eqn(1) to get the required result
Hope it helps
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