Question

prove that tan^-1(x)+tan^-1 2x÷1-x^2=tan^-1(3x-x^3)÷1-3x^2​

Answer 1

Answer:

tan^-1 is measure by tan¹

tan¹A + tan¹B = tan¹[(A+B) ÷1-AB]

so,

tan¹(x) + tan¹[(2x)÷1-x²] = tan¹[(x+(2x)÷1-x²) ÷1-(x).(2x)÷1-x²]

=> tan¹{[(x)*(1-x²) + (2x)] ÷[1-x² -