Question

Prove that tan 13A- tan9A-tan4A=tan13Atan9Atan4A taking lhs only

Answer 1

it is answer
Hope it will help u

Answer 2

tan 13A - tan 9A - tan 4A = tan 13A tan 9A tan 4A is proved

Given :

tan 13A - tan 9A - tan 4A = tan 13A tan 9A tan 4A

To find :

To prove the expression

Formula :

$\displaystyle \sf{ tan \:( x + y) = \frac{tan \: x +tan \: y }{1 -tan \: x \: tan \: y } }$

Solution :

Step 1 of 2 :

Write down the given expression to prove

The expression is

tan 13A - tan 9A - tan 4A = tan 13A tan 9A tan 4A

Step 2 of 2 :

Prove the expression

$\sf tan 13A= tan \: (9A + 4A)$

$\displaystyle \sf{ \implies tan 13A= \frac{tan \: 9A +tan \: 4A }{1 -tan \: 9A \: tan \: 4A } }$

$\displaystyle \sf{ \implies tan 13A - tan 13A \: tan 9A \: tan 4A =tan 9A + tan 4A }$

$\displaystyle \sf{ \implies tan 13A - tan 9A - tan 4A = tan 13A tan 9A tan 4A}$

Hence the proof follows

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