Question

Prove that tan 15° + tan 75° = sec ^2 15°/sec ^2 15°-1

Answer 1

Step-by-step explanation:

Now,

tan15°

+tan75°

=tan15 °

+cot15 °

[ Since tan75 °

=cot15°]

=tan15 °+

tan15°

1

=

tan15 °

1+tan

2

15°

=

sec ²

15 °

−1

sec ²

15 °

[ As sec ²

15 °

=1+tan

²

15 °