Math, asked by shifaaps987, 1 year ago

Prove that tan^2 A -tan^2B=(sin^2A-sin^2B)/cos^2A.cos^2B)

Answers

Answered by loveykhehra

1

take l.h.s=r.h.s
sin^2A/cos^2A-sin^2A/cos^2A
(sin^2A-sin2^A)/(cos^2A.cos^2A)

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