Math, asked by thenameisuday02, 3 months ago

prove that: tan^2θ−sin^2θ=tan^2θ.sin^2θ

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Answers

Answered by XxHATERxX
7

Answer:

➡️tan²∅-sin²∅=sin²∅-cos²∅

_____

cos²∅

➡️sin²∅(1-cos²∅)

_____________

cos²∅

➡️sin²∅

_______. sin²∅

cos²∅

➡️tan²sin²∅-sin²∅=tan²∅.sin²∅

➡️tan²∅sin²∅ > 0(always)

__

➡️tan²∅ > sin²∅

__

Step-by-step explanation:

hope you appreciate this ans

Answered by Anonymous
1

Answer:

Step-by-step-explanation:

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