Question

Prove that Tan^2A/(1+tan^2A)+cot^2A/1+cot^2A)=1

Answer 1

Hey There,

Here, we will only use one simple relation: 
$\cot A = \frac{1}{\tan A}$


Let's take your question:

$LHS \\ \\ \\ =\frac{\tan^2A}{1+\tan^2A}+\frac{\cot^2A}{1+\cot^2A} \\ \\ \\ = \frac{\tan^2A}{1+\tan^2A} + \frac{\frac{1}{\tan^2A}}{1+\frac{1}{\tan^2A}} \\ \\ \\ = \frac{\tan^2A}{1+\tan^2A} + \frac{\frac{1}{\tan^2A}}{\frac{1+\tan^2A}{\tan^2A}} \\ \\ \\ = \frac{\tan^2A}{1+\tan^2A} + \frac{1}{1+\tan^2A} \\ \\ \\ = \frac{1+\tan^2A}{1+\tan^2A} \\ \\ \\ = 1 \\ \\ \\ = RHS$

Hope it helps
Purva
Brainly Community

Answer 2

hope this helps....
if u don't understand any step don't report..
first tell me so I can edit and make u understood...

and if understand mark as brainlist plzz