Question

prove that tan^2A - sin^2A = tan^2A sin^2A

Answer 1

hey dear

here is your answer

Solution

TanA = TanA

squaring on both the sides

tan^2A = tan^2A

Breaking tan to Sin / Cos

Sin^2A / Cos^2A = tan^2 A

using sin square + cos square = 1

( 1 - Cos^2A ) - 1 = tan^2A

Multiply both sides by Sin square A

( Sin^2A / Cos^2A) - Sin^2A = ( tan^2A) Sin^2A

Again write sin / cos as tan


Tan^2A - Sin^2A = ( tan ^2 A) ( sin^2A)

Hence proved


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