Question

prove that tan^2A×sin^2A=tan^2A-sin^2A​

Answer 1

taking RHS tan^2A - sin^2A

tan^2A - sin^2A = sin^2A/cos^2A - sin^2A

=sin^2A - sin^2A cos^2A/cos^2A

=sin^2A(1 - cos^2A/cos^2A)

=sin^2A(sin^2A/cos^2A). (by the identity sin^2 + cos^2 = 1)

=sin^2A × tan^2A

hope it helps you

keep smiling

Answer 2

Answer:

Step-by-step explanation:

Tan^2A×sin^2A=tan^2A-sin^A

Taking RHS

Tan^2A-sin^2A

Sin^2A/cos^A -sin^2A

Taking common sin^2A

Sin^A(1/cos^2-1)

Sin^2(1-cos^2/cos^2)

Sin^2(sin^2/cos^2)

Sin^2×tan^2