Question

prove that tan^2theta+cot^2theta=sec^2theta.cosec^2theta-2
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Answer 1

Answer:

solved

Step-by-step explanation:

let theta =

LHS = tan^2theta+cot^2theta = tan²∝+cot²∝ = sin²∝/cos²∝+cos²∝/sin²∝

=  sin^4∝ + cos^4∝ ÷ sin²∝cos²∝

= ( cos²∝+sin²∝)² - 2sin²∝cos²∝ ÷ sin²∝cos²∝

= (1 - 2sin²∝cos²∝) ÷ sin²∝cos²∝

= 1/sin²∝cos²∝  - 2

= sec²∝cosec²∝ - 2

= RHS

Answer 2

Wrong Question:-

$\cancel{prove \: that \: {tan }^{2} \theta +cot^2 \theta=sec^2 \theta.cosec^2 \theta-2.}$

$\bold {\underline {Solution:-}}$