Question

prove that tan^2theta-sin^2theta = tan^2theta ×sin^2theta​

Answer 1

Answer:

hope it will help you:-)

Answer 2

Prove:

tan²@ - sin²@ = tan²@.sin²@

Solution:

L.H.S

$\tan ^{2}x - { \sin}^{2}x \\ \\ \frac{ \sin ^{2} \: x}{ \cos ^{2} x} - sin ^{2} x \\ \\ sin ^{2} x( \frac{1}{cos ^{2} x} - 1) \\ \\ sin ^{2} x ( \frac{1 - cos ^{2} x}{cos ^{2}x } ) \\ \\ sin ^{2} x. \frac{sin ^{2} x}{cos ^{2}x } \\ \\ sin ^{2}x .tan ^{2} x$

.'. L. H. S = R. H. S