Prove that tan(π/4 - x) = (1-tanx)/(1+tanx)
Answers
Answered by
1
Step-by-step explanation:
LHS = tan(π/4 - x)
using tan(x-y) = tanx-tany/1+ tanxtany
now,
LHS = tan(π/4 - tanx) / 1+ tanπ/4tanx
= 1- tanx/1+ tanx (since tanπ/4 = 1 )
therefore RHS = LHS
(Hence proved )
Similar questions