Math, asked by mrinmoyee1974, 5 months ago

Prove that tan 47°+ cot 27°/ tan 43° + cot 63°= tan 43ºcot 63°

Answers

Answered by govindghatteppanavar

1

Answer:

tan 47° + cot 27° / tan 43° + cot 63°

tan 47° × tan 43° / cot 43° × cot 63

tan (90°-47) × tan 43 ° / cot(90°-27) × cot 63°

1/tan43°× tan 43° / 1/cot 63° × cot 63°

:- tan 43° cot 63°

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