Question

Prove that tan 56° = Cos 11° +Sin 11° /Cos 11°-Sin 11°


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Answer 1

Step-by-step explanation:

Given , cosec2θ=33–√cotθ−5cosec2θ=33cotθ-5

Given , cosec2θ=33–√cotθ−5cosec2θ=33cotθ-5⇒1+cot2θ−33–√cotθ+5=0⇒1+cot2θ-33cotθ+5=0

Given , cosec2θ=33–√cotθ−5cosec2θ=33cotθ-5⇒1+cot2θ−33–√cotθ+5=0⇒1+cot2θ-33cotθ+5=0[since , cosec2θ=1+cot2θ][since , cosec2θ=1+cot2θ]

Given , cosec2θ=33–√cotθ−5cosec2θ=33cotθ-5⇒1+cot2θ−33–√cotθ+5=0⇒1+cot2θ-33cotθ+5=0[since , cosec2θ=1+cot2θ][since , cosec2θ=1+cot2θ]⇒cot2θ−33–√cotθ+6=0⇒cot2θ-33cotθ+6=0

Given , cosec2θ=33–√cotθ−5cosec2θ=33cotθ-5⇒1+cot2θ−33–√cotθ+5=0⇒1+cot2θ-33cotθ+5=0[since , cosec2θ=1+cot2θ][since , cosec2θ=1+cot2θ]⇒cot2θ−33–√cotθ+6=0⇒cot2θ-33cotθ+6=0Work with option , we find that

Given , cosec2θ=33–√cotθ−5cosec2θ=33cotθ-5⇒1+cot2θ−33–√cotθ+5=0⇒1+cot2θ-33cotθ+5=0[since , cosec2θ=1+cot2θ][since , cosec2θ=1+cot2θ]⇒cot2θ−33–√cotθ+6=0⇒cot2θ-33cotθ+6=0Work with option , we find thatThis equation is satisfied by θ=π6θ=π6.

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Answer 2

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