Question

Prove that tan 6° × tan 21° × tan 30° × tan 69° × tan 84° = 1/√3

Answer 1

$\rule{400}4$

▪︎ See the ATTACHMENT For Correct Proof.

$\rule{400}4$

▪︎ More IDs related Trigonometry:-

$\\ \tt\leadsto \tan\theta = \cot(90 - \theta) \\ \\ \tt\leadsto \cot \theta = \tan(90 - \theta) \\ \\ \tt\leadsto \sin\theta = \cos(90 - \theta) \\ \\ \tt\leadsto \cos\theta = \sin(90 - \theta) \\ \\ \tt\leadsto cosec\theta = \sec(90 - \theta) \\ \\ \tt\leadsto \sec\theta = cosec(90 - \theta)$

$\rule{400}4$